从开始和结束日期开始活跃的几周 [英] Get active weeks from start and end date

问题描述

我有如下订阅数据.数据显示用户何时购买了订阅.它具有 user_id，subscription_id，开始日期和结束日期.

I have subscriptions data as shown below. The data shows when a user bought a subscription. It has user_id,subscription_id,start date and end_date.

我从中派生了 wk_start 和 wk_end .

+------+-----------------+------------+------------+----------+--------+
| user | subscription_id |   start    |    end     | wk_start | wk_end |
+------+-----------------+------------+------------+----------+--------+
|    1 | 1A              | 2019-06-01 | 2019-06-30 |       22 |     27 |
|    2 | 2A              | 2019-06-01 | 2019-06-21 |       22 |     25 |
|    3 | 3A              | 2019-06-01 | 2019-06-21 |       22 |     24 |
|    1 | 1B              | 2019-07-04 | 2019-08-04 |       27 |     29 |
|    2 | 2B              | 2019-07-01 | 2019-07-31 |       27 |     31 |
+------+-----------------+------------+------------+----------+--------+

现在，我想以一种方式转换数据，以便对于每个 user，subscription_id ，我将获得特定用户的活动周数.

Now I want to transform the data in a such a way that for each user,subscription_id, I will get the active weeks for a particular user.

所需的输出如下

+------+-----------------+------+
| user | subscription_id | Week |
+------+-----------------+------+
|    1 | 1A              |   22 |
|    1 | 1A              |   23 |
|    1 | 1A              |   24 |
|    1 | 1A              |   25 |
|    1 | 1A              |   26 |
|    1 | 1A              |   27 |
|    2 | 2A              |   22 |
|    2 | 2A              |   23 |
|    2 | 2A              |   24 |
|    2 | 2A              |   25 |
|    3 | 3A              |   22 |
|    3 | 3A              |   23 |
|    3 | 3A              |   24 |
|    1 | 1B              |   27 |
|    1 | 1B              |   28 |
|    1 | 1B              |   29 |
|    2 | 2B              |   27 |
|    2 | 2B              |   28 |
|    2 | 2B              |   29 |
|    2 | 2B              |   30 |
|    2 | 2B              |   31 |
+------+-----------------+------+

它基本上扩展了订阅数据，使每个用户的活动周有效.

It basically expands the subscriptions data to get active weeks for each user.

例如，具有 subscription_id 1A 的用户1 在22周至27周处于活动状态.

For example user 1 with subscription_id 1A was active from week 22 till 27.

具有 subscription_id 2A 的用户2 在第22周到第25周一直处于活动状态.

Similarly user 2 with subscription_id 2A was active from week 22 till 25.

现在，用户2 从27周到31年再次处于活动状态，并且 subscription_id 2B

Now user 2 was again active from week 27 till 31 with subscription_id 2B

我希望这有助于了解预期的结果

I hope this helps to understand the desired result

我在这里制作了 db-fiddle .(尽管它在mysql)，但应该以其他方式提供帮助

I have made a db-fiddle here.(though it's in mysql) but should help in some or the other way

推荐答案

您可以创建一个包含所有星期数的表，并对它进行部分笛卡尔连接，如下所示:

You can create a table that includes all week numbers and do a partial cartesian join against it, something like this:

CREATE TABLE weeks (
  `week` INTEGER 
);

INSERT INTO weeks
  (`week`)
VALUES
         (1),  (2),  (3),  (4),  (5),  (6),  (7),  (8),  (9)
, (10), (11), (12), (13), (14), (15), (16), (17), (18), (19)
, (20), (21), (22), (23), (24), (25), (26), (27), (28), (29)
, (30), (31), (32), (33), (34), (35), (36), (37), (38), (39)
, (40), (41), (42), (43), (44), (45), (46), (47), (48), (49)
, (50), (51), (52), (53)
;

SELECT t1.user, t1.subscription_id, w.week
FROM table1 t1
CROSS JOIN weeks w
WHERE w.week BETWEEN t1.wk_start and t1.wk_end
ORDER BY t1.user, t1.subscription_id, w.week;

https://www.db-fiddle.com/f/mn4towXxscmLsibQjwtNEH/0

周"表似乎有点麻烦，但只需创建一次即可，然后您就可以忘记它了.

The weeks table seems like a bit of a nuisance, but it just has to be created once and then you can forget about it.

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