从Java的Desktop.getDesktop().browse(URI uri);设置查询字符串. [英] Setting a query string from Java's Desktop.getDesktop().browse(URI uri);

问题描述

我尝试使用Google谷歌搜索，但找不到答案.我正在编写一个纯Java桌面应用程序.通过使用Desktop类浏览功能并为其提供URI，可以启动帮助系统.当我添加?"时，Java中的URI失败.我想将程序版本号传递到浏览器中的脱机帮助页面，但是我不知道如何设置查询字符串.

I have tried googling but I cannot find an answer. I am writing a pure Java Desktop application. The help system launches by using the Desktop class browse function and giving it a URI. When I add a "? then the URI fails in Java. I want to pass the program version number to my offline help page in the browser, but I cannot figure out how to set a query string.

我正在RedHat 6上运行.我正在使用以下代码:

I am running on RedHat 6. I am using this code:

uri = new URI("file", "", programPath, "version=1.0.3", "");
Desktop.getDesktop().browse(uri);

我在浏览功能上得到一个IOException.它只说无法显示URI:"

I get an IOException on the browse function. All it says is that "Failed to show URI:"

如果我使用完整的uri路径并将其粘贴到我的浏览器中，它将起作用.我对此深感困惑……

If I take that full uri path and paste it in my browser, it works. I am completely stumped by this...

推荐答案

好的，所以我从来没有像我想要的那样工作，但是如果我使用只接受字符串的URI构造函数，然后将路径作为正常，总是可以正常工作，然后添加#+ versionNumberVar"；然后就可以了！这很令人沮丧，因为它不能与?version =" + versionNumberVar一起使用，但是我终于有了我需要的东西.而且，那些其他构造函数对我不起作用，这令人惊讶.不幸的是，URI错误消息是含糊的，并且只显示无法显示URI".

Okay so I never got it working the way I wanted to, but if I use the URI constructor that just takes a string and then I feed it the path as normal which always worked and then add "# + versionNumberVar"; then it works! It is frustrating because it won't work with "?version=" + versionNumberVar but I have what I need finally. Also, those other constructors do not work for me which is surprising. Unfortunately the URI error messages are cryptic and it just says "Failed to show URI".

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