使用javascript创建元素 [英] Create an element using javascript
问题描述
我有一个html表
<table id = "rpttable" name = "rpttable">
<thead>
Column Headers here...
</thead>
<tbody id = "rptbody" name = "rptbody">
data here <3 ....
</tbody>
</table>
这是我的php(sample.php)
and here is my php (sample.php)
<?php
Query Code here..
Query Code there..
and so on
//this is the way I populate a table
while (query rows) {
echo '<tr>';
echo '<td>Sample Data</td>';
echo '</tr>;
}
?>
因此,要执行此操作并填充表格,这就是我要做的事情.
So to make this work and to populate the table this is what I do.
<table id = "rpttable" name = "rpttable">
<thead>
Column Headers here...
</thead>
<tbody id = "rptbody" name = "rptbody">
<?php
include 'folder_location/sample.php';
?>
</tbody>
</table>
忽略输出的图像,但是当我转到 Inspect Element
甚至是 Ctrl + u
时,我现在将看到我的表结构是这样的.
Disregard the image of the ouput but when I go to Inspect Element
or even Ctrl + u
I will see my table structure now is like this.
<table id = "rpttable" name = "rpttable">
<thead>
Column Headers here...
</thead>
<tbody id = "rptbody" name = "rptbody">
<tr>
<td>Sample Data</td>
</tr>
</tbody>
</table>
现在这是东西.我不这样做,这就是我要做的.
Now here is the thing. I do not do that this is what I do.
$("#rpttable tr").remove();
for (i = 0; i < data.length; i++) {
tr = $("<tr />");
for (x in data[i]) {
td = $("<td />");
td.html(data[i][x]);
tr.append(td);
}
rpttable.append(tr);
}
相同的输出它确实填充了表格,但是当我转到 Inspect Element
甚至是 Ctrl + u
时,输出是.
Same output It does populate the table but when I go to Inspect Element
or even Ctrl + u
the output is.
<table id = "rpttable" name = "rpttable">
<thead>
Column Headers here...
</thead>
<tbody id = "rptbody" name = "rptbody">
**This is the part missing**
</tbody>
</table>
我在这里的问题是如何从字面上创建使用usung javascript/ajax的元素?在PHP相同的输出.我的意思是写元素.
My question here is how can I literaly create an element usung javascript/ajax? same output in php. I mean write the element.
**更新**我正在尝试从外部文件运行css类,如果我根据自己的需要手动对其进行编辑,则我将花费一个小时,并且这也很难解释其用于表的类.我尝试使用< table>
中的默认值使用该类.您知道手动将其写在后端.现在我正在尝试使用php和ajax填充它,到目前为止,它确实可以填充,但是当我尝试运行该类时,该类不起作用.
** Updated **
I am trying to run a css class from an external file and If I manualy edit it to suits my needs I will a long hour and also Its hard for me to explain its a class for table. I tried to use that class using default value in <table>
. You know manualy write it at the back end. now Im trying to populate it using a php and ajax so, so far so good it does populate but when I try to run the class the class does not work.
TYSM
推荐答案
尝试一下:
$("#rpttable tbody tr").remove();
var content = '' ;
for (i = 0; i < data.length; i++) {
content += "<tr>" ;
for (x in data[i]) {
content += "<td>" + data[i][x] + "</td>" ;
}
content += "</tr>" ;
}
$("#rpttable tbody").html(content) ;
已更新
我也在使用Google Chrome.请尝试以下代码,并在每次添加新行时检查检查元素.您可以在检查元素
中看到 html
发生变化!
I am using Google Chrome too. Please try the below code, and check the inspect element each time you add a new row. You can see the html
in the Inspect Element
changing!
function AppendNewRowToTable() {
var trLen = $("table tbody tr").length ;
var content = "" ;
content += "<tr>" ;
for (i = 0; i < 5; i++) {
content += "<td>" + trLen + "-" + i + "</td>" ;
}
content += "</tr>" ;
$("table tbody").append(content) ;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<a href="javascript:;" onclick="AppendNewRowToTable()">Add new Row</a>
<br />
<table>
<thead>
<tr>
<th>Title 01</th>
<th>Title 02</th>
<th>Title 03</th>
<th>Title 04</th>
<th>Title 05</th>
</tr>
</thead>
<tbody></tbody>
</table>
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