将PHP变量作为输入字段的值 [英] Echo PHP variable as an value of input field

问题描述

我有一个带有多个输入标签的简单HTML表单.在页面加载时，我向表单提供数据以从数据库中回显字段的当前值，然后用户可以修改这些值并再次提交以执行更新.

I have a simple HTML form with multiple input tags. On page load i provide data to the form to echo the current value of field from database and than user can modify those values and submit again to perform an update.

<input type="text" name="nameMember" id="nameMember" value=<?php echo (isset($nameMember)) ? $nameMember: ''?>>

代码可以正常工作，只是它不显示完整的变量.

Code works fine except that it do not display complete variable.

例如，如果$ nameMember ='Saurabh Pradhan'而不是显示'Saurabh Pradhan'作为输入标签的值，则仅显示'Saurabh'.

For example, If $nameMember = 'Saurabh Pradhan' than instead of showing 'Saurabh Pradhan' as value of input tag it only shows 'Saurabh'.

如果我从数据中删除空格并将其设置为"SaurabhPradhan"，则会显示完整名称.基本上只删除空格后的文本.

If i remove the space from the data and make it to 'SaurabhPradhan' it displays complete name. Basically it is only removing the text after space.

推荐答案

HTML属性值通常应用引号引起来:

HTML attribute values should generally be wrapped in quotes:

<input type="text" name="nameMember" id="nameMember" value="<?php echo (isset($nameMember)) ? $nameMember: ''?>">

与您对 type 和 name 属性所做的完全一样

exactly as you already do with the type and name attributes

value 属性没有什么不同

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