将MATLAB中的find()转换为python [英] Converting find() in matlab to python

问题描述

我正在将代码从Matlab转换为Python.Matlab中的代码是:

I am converting a code from Matlab to Python. The code in Matlab is:

x = find(sEdgepoints > 0 & sNorm < lowT);
sEdgepoints(x)=0;

两个数组的大小相同，我基本上是在创建蒙版.

Both arrays are of same size, and I am basically creating a mask.

我阅读了这里 numpy中的nonzero()等同于find()，因此我使用了它.在Python中，我将dstc用于sEdgepoints，将dst用于sNorm.我也直接输入了lowT =60.所以，代码是

I read here that nonzero() in numpy is equivalent to find(), so I used that. In Python, I have dstc for sEdgepoints and dst for sNorm. I have also directly put in lowT = 60. So, the code was

x = np.nonzero(dstc > 0 and dst < 60)
dstc[x] = 0

但是，我收到以下错误消息:

But, I get following error:

Traceback (most recent call last):
File "C:\Python27\Sheet Counter\customsobel.py", line 32, in <module>
    x = np.nonzero(dstc > 0 and dst < 60)
ValueError: The truth value of an array with more than one element is 
ambiguous. Use a.any() or a.all()

我阅读了有关a.any()/a.all()的用法在这篇文章中，我不确定该如何运作.因此，我有两个问题:1.如果可以，使用哪个数组?2.如果我是正确的但它不起作用，如何转换代码?

I read about the usage of a.any()/a.all() in this post, and I am not sure how that will work. So, I have two questions: 1. If it does, which array to use? 2. If I am correct and it does not work, how to convert the code?

推荐答案

和进行布尔运算，而numpy希望您进行按位运算，因此必须使用& 即

and does boolean operation and numpy expects you to do bitwise operation, so you have to use & i.e

x = np.nonzero((dstc > 0) & ( dst < 60))

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