如何打印 pandas DataFrame的特定行? [英] How to print a specific row of a pandas DataFrame?

问题描述

我有一个庞大的数据框，但出现错误:

I have a massive dataframe, and I'm getting the error:

TypeError :(空'DataFrame':没有要绘制的数字数据"，出现在索引159220上)"

我已经删除了空值，并检查了DataFrame的dtypes，所以我不知道为什么它在那一行上失败了.

I've already dropped nulls, and checked dtypes for the DataFrame so I have no guess as to why it's failing on that row.

如何仅打印数据帧的那一行(索引159220)?

How do I print out just that row (at index 159220) of the data frame?

谢谢

推荐答案

当您使用标量值调用 loc 时，会得到一个 pd.Series .然后，该系列将具有一个 dtype .如果要查看数据帧中的行，则需要将类似索引器的数组传递给 loc .

When you call loc with a scalar value, you get a pd.Series. That series will then have one dtype. If you want to see the row as it is in the dataframe, you'll want to pass an array like indexer to loc.

用另外一对方括号包裹索引值

Wrap your index value with an additional pair of square brackets

print(df.loc[[159220]])

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