在Python中按属性获取对象列表中的索引 [英] Get index in the list of objects by attribute in Python

问题描述

我有具有属性ID的对象列表，并且我想查找具有特定ID的对象的索引.我写了这样的东西:

I have list of objects with attribute id and I want to find index of object with specific id. I wrote something like this:

index = -1
for i in range(len(my_list)):
    if my_list[i].id == 'specific_id'
        index = i
        break

但是看起来不太好.有更好的选择吗?

but it doesn't look very well. Are there any better options?

推荐答案

如果要在 for 循环中使用值和索引，请使用枚举:

Use enumerate when you want both the values and indices in a for loop:

for index, item in enumerate(my_list):
    if item.id == 'specific_id':
        break
else:
    index = -1

或者，作为生成器表达式:

Or, as a generator expression:

index = next((i for i, item in enumerate(my_list) if item.id == 'specific_id'), -1)

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