"Hello" .indexOf(“")返回0 [英] "Hello".indexOf("") returns 0

问题描述

如果我尝试在String中找到空字符的索引，我只是试图找出编译器的工作方式.我记得有人总是将空字符附加在字符串的末尾，所以我期望代码下面给我5.

I Just tried to find out what the compiler does if I try to find the index of a null charachter in a String.I remember somehwere that a null charachter is always appended to the end of a string, so i expected the code below to give me 5.

当我输入以下内容时:

String s = "Hello";
System.out.println(s.indexOf(""));

输出为0

请帮助！

推荐答案

首先，如果您要查找空字符，则可能要执行(char)0 ，因为"是一个空字符串(无字符).

First, if you were looking for a null character you would probably want to do (char)0 because "" is an empty string (no character).

第二，如果Java使用空字符(不必使用IIRC)，则它们会将其隐藏.

Second, if Java uses a null character (they don't have to IIRC) then they hide it.

碰到我的第三点，因为我不确定了.

Struck my third point because I'm not sure about it anymore.

第二我查了一下，Java字符串不是null终止的.他们依靠长度字段.

SECOND I looked it up, Java strings are not null terminated. They rely on the length field.

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