如何从C中具有领先空格的stdin获取字符串输入? [英] How to get a string input from stdin that has leading white space in C?

问题描述

需要一种使输入字符串以空格开头的解决方案吗?

Need a solution to get input string start with spaces?

我知道一种在输入中包含空格的方法

I know a method to include space in input

scanf("%[^\n]s", s);

但是它仅适用于单词之间的间隔.我需要一个以空格开头的字符串的解决方案.而且我还需要变量中的起始空格

But its working only for space between words. I need a solution for string starts with spaces. And I also need the starting spaces in the variable

推荐答案

要获取用户输入的行，请使用 fgets().

To get a line of user input, use fgets().

#define S_MAX_LENGTH
char s[S_MAX_LENGTH + 2];
if (fgets(s, sizeof s, stdin)) {
  s[strcspn(s, "\n")] = '\0'; // Should code want to lop off a potential trailing \n
  ....

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请勿使用 scanf(％[^ \ n] s"，s); 或 gets(s); .它们遭受缓冲区溢出和其他问题的困扰.

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Do not use scanf("%[^\n]s", s); nor gets(s);. They suffer from buffer overflow and other issues.

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