将Integer拆分为两个单独的Integer [英] Split Integer into two separate Integers

问题描述

假设我有

int n=123456;
int x,y=0;

如何拆分整数"n"?分两半.

How do I split the integer "n" in two half.

注意: n 中的总位数始终是2的倍数，例如 1234、4567、234567、345621等...都具有2,4，6,8位数字.我想将它们分成两半.

Note : The Total Number of digits in n will always be multiple of 2, e.g. 1234, 4567, 234567, 345621 etc... all have 2,4,6,8 digits. I want to divide them in half.

我正在尝试使用以下代码，但无法正常工作， y 变量以某种方式保留了相反的第二部分.

I am trying with following Code but it's not working, the y variable is holding reversed second part somehow.

int x, y=0, len, digit;
int n=123456;

len=floor(log10(abs(n))) + 1;
x=n;
while((floor(log10(abs(x))) + 1)>len/2)
{
    digit=x%10;
    x=x/10;
    y=(y*10)+digit;
}
printf("First Half = %d",x);
printf("\nSecond Half = %d",y);

当输入为时:

n = 123456;

n=123456;

我得到的输出:

上半场= 123
下半场= 654

First Half = 123
Second Half = 654

我想要的输出:

上半场:123

First Half : 123

下半场:456

推荐答案

这是一个演示程序.除了printf之外，它不使用任何功能.:)因此，这是最简单的解决方案.

Here is a demonstrative program. It does not use any function except printf.:) Thus it is the simplest solution.

#include <stdio.h>

int main( void )
{
    unsigned int a[] = { 12, 1234, 123456, 12345678, 1234567890 };
    const unsigned int Base = 10;

    for ( size_t i = 0; i < sizeof( a ) / sizeof( *a ); i++ )
    {   
        unsigned int divisor = Base;
        while ( a[i] / divisor > divisor ) divisor *= Base;

        printf( "%u\t%u\n", a[i] / divisor, a[i] % divisor );
    }        
}

程序输出为

1       2
12      34
123     456
1234    5678
12345   67890

如果您要使用带符号的整数类型和负数，则程序可以采用以下方式

If you are going to use a signed integer type and negative numbers then the program can look the following way

#include <stdio.h>

int main( void )
{
    int a[] = { -12, 1234, -123456, 12345678, -1234567890 };
    const int Base = 10;

    for ( size_t i = 0; i < sizeof( a ) / sizeof( *a ); i++ )
    {   
        int divisor = Base;
        while ( a[i] / ( a[i] < 0 ? -divisor : divisor ) > divisor ) divisor *= Base;

        printf( "%d\t%d\n", a[i] / divisor, a[i] % divisor );
    }        
}

其输出为

-1      -2
12      34
-123    -456
1234    5678
-12345  -67890

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