final = P *((((1 +(r/n))**(n * t))))TypeError:/不支持的操作数类型:' str'和' int' [英] final = P * (((1 + (r/n)) ** (n*t))) TypeError: unsupported operand type(s) for /: 'str' and 'int'

问题描述

我是Python的新手(运行Python 3)，已经搜索了所有位置，但仍然停留在此位置.我知道我有一个字符串，但需要将其转换为整数作为最终答案.下面是我输入的用于测试的代码.我被卡在我得到的错误上.这是用于复利计算器的，用户必须输入本金，年利率，复利频率和年份.我进行了一些研究，发现我可以对p，n和r使用('inf')作为声明，说可以是大数或小数.基本上，用户可以输入任何数字.

I'm new to Python (running Python 3), have searched every where and still stuck on this. I understand that I have a string but need to get it into a integer as a final answer. Below is the code I inputted to test it out. I'm stuck on the error that I get. This is for a compound interest calculator where the user has to input the principal, annual interest rate, how often it's compounded, and the year(s). I did some research and noticed that i can use ('inf') for p,n,and r as a statement saying either can be large or small numbers. Basically the user can input any number.

P = 10000
n = 12
r = 0.08

p = int(input("Enter starting principle please. "))
n = int(input("Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) "))
r = input("Enter annual interest amount. (decimal) ")
t = int(input("Enter the amount of years. "))

final = P * (((1 + (r/n)) ** (n*t)))

print ("The final amount after", p, "years is", final)

错误:

Enter starting principle please. 75000
Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) 12
Enter annual interest amount. (decimal) 0.03
Enter the amount of years. 15
Traceback (most recent call last):
  File "C:\Users\Joshua\AppData\Local\Programs\Python\Python35-32\Program Five.py", line 10, in <module>
    final = P * (((1 + (r/n)) ** (n*t)))
TypeError: unsupported operand type(s) for /: 'str' and 'int'

这是我第一次使用此网站，如果我遗漏了任何信息，请告诉我.我乐于接受任何可以帮助我解决此问题的建议.

This is my first time using this site, if I left out any information please let me know. I'm open to any suggestions that will help me fix this issue.

                             Edit

抱歉，请耐心等待.好的，我相信通过Stop and Think的@Rafael Cardoso建议，它可以正常工作.谢谢你.

Sorry for the wait. Okay I believe I got it to work correctly going by @Rafael Cardoso recommendation of Stop and Think. Thank you for that.

P = 10000
n = 12
r = 0.08

p = int(input("Enter starting principle please. "))
n = int(input("Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) "))
r = float(input("Enter annual interest amount. (decimal) "))
t = int(input("Enter the amount of years. "))

final = P * (((1 + (r/n)) ** (n*t)))

print ("The final amount after", p, "years is", final)

当我运行它时，没有错误弹出.我喘口气后才发现是('inf')引起问题的原因，如果我将p，n，r留在原处，那没有问题.

When I run it, no errors pop up. I found out after taking a breather that the ('inf') was causing the issue, if I leave p,n,r with whats there it works with no issues.

再次感谢大家！

推荐答案

根据堆栈跟踪， r 是 str .您应该只使用数字，因此为了进行操作，请将r转换为 float (因为它处理十进制数字)

According to the stacktrace, r is a str. You should work with numbers only, so in order to do the operation, convert r to float (as it deals with decimal numbers)

r = float(input("Enter annual interest amount. (decimal) "))

编辑

好吧，让我们停下来思考.当您使用 python 3 时，输入函数会将您输入的值存储为字符串(即文本).您希望它们成为数字.

Edit

Ok, lets stop and think. As you are using python 3 , the input function will store the value you input as a string (i.e. as text). You want them to be numbers.

因此，您必须将所有内容都转换为数字，以便能够相乘，除等.例如，"a"/"b" 是什么意思?那么"a1"/"b2" 呢?甚至是"1"/"2" ?他们没有道理.但是， 1/2 是有意义的.区别在于，我们在前三个示例中处理文本，而在最后一个示例中处理数字.

So, you have to convert everything to numbers so that you are able to multiply, divide etc. For example, what does "a"/"b" means? And what about "a1"/"b2"? Or even "1"/"2"? They make no sense. However, 1/2 makes sense. The difference is that we are dealing with text in the first 3 examples, and with numbers in the last example.

要使其正常工作，您应该将所有内容都转换为 int 或 float .这些 types 是数字，您可以不用担心就可以对它们进行数学运算.

To make it work, you should convert everything either to int or to float. These types are numbers, and you can do mathematical operations with them without worries.

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