正则表达式以匹配JSON列表中的特定多行对象 [英] Regex to match specific, multiline object in JSON list

问题描述

我使用的JSON列表如下所示:

I work with JSON lists which can look somewhat like the following:

 [
    {
      "accessType": "*",
      "principalType": "ROLE",
      "principalId": "$unauthenticated",
      "permission": "DENY"
    },
    {
      "accessType": "*",
      "principalType": "ROLE",
      "principalId": "$everyone",
      "permission": "DENY"
    },
    {
      "accessType": "*",
      "principalType": "ROLE",
      "principalId": "$owner",
      "permission": "ALLOW"
    }
  ]

编写正则表达式以正确地仅提取包含单词 $ everyone 的列表项的正确方法是什么?我需要提取整个对象，所以正确的结果应该是:

What would be the proper way to write a regex which correctly extracts only the list item which contains the word $everyone? I need to extract the entire object, so the correct result should be:

   {
     "accessType": "*",
     "principalType": "ROLE",
     "principalId": "$everyone",
     "permission": "DENY"
   }

我尝试了类似 \ {(?s).* Everyone(?s).* \} 之类的方法，但这将与列表中的第一个和最后一个大括号和最后一个大括号匹配，介于两者之间.

I have tried something like \{(?s).*everyone(?s).*\}, but this will match the first and last opening and closing curly bracket in the list, with everything in between.

推荐答案

对于在IDE中进行一次搜索和替换的一次性任务:

For a one-off task of search and replace in IDE:

\{[^}]*?everyone[^}]*\}

如果您需要 $ ，请使用以下任一方法:

If you need the $, use either:

\{[^}]*?\$everyone[^}]*\}
\{[^}]*?[$]everyone[^}]*\}

而不是(?s).* ，它允许在 {和 Everyone 之间以及在 Everyone 之间的任何内容和} ，我将其限制为 [^}] *?，这不允许在免费"部分中使用} .

Instead of (?s).* which allows anything in between { and everyone and between everyone and }, I restrict it to [^}]*?, which disallows } in the "free" part.

正则表达式中有很多假设，因此一般情况下不要使用它.

A lot of assumptions is made in the regex, so don't use it in general case.

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