使用`pandas.cut()`,我如何获得整数箱并避免获得负的最低界限? [英] With `pandas.cut()`, how do I get integer bins and avoid getting a negative lowest bound?
问题描述
我的数据框的最小值为零.我正在尝试使用 pandas.cut()
的 precision
和 include_lowest
参数,但我无法获得由整数组成的区间比浮点数小数点后一位.我也无法让最左边的间隔停在零.
My dataframe has zero as the lowest value. I am trying to use the precision
and include_lowest
parameters of pandas.cut()
, but I can't get the intervals consist of integers rather than floats with one decimal. I can also not get the left most interval to stop at zero.
import pandas as pd
import seaborn as sns
import matplotlib.pyplot as plt
sns.set(style='white', font_scale=1.3)
df = pd.DataFrame(range(0,389,8)[:-1], columns=['value'])
df['binned_df_pd'] = pd.cut(df.value, bins=7, precision=0, include_lowest=True)
sns.pointplot(x='binned_df_pd', y='value', data=df)
plt.xticks(rotation=30, ha='right')
我尝试将 precision
设置为-1、0和1,但是它们都输出一个十进制浮点数. pandas.cut()
帮助确实提到x-min和x-max值扩展了x-range的0.1%,但我认为 include_lowest
可能以某种方式抑制这种行为.我目前的解决方法是导入numpy:
I have tried setting precision
to -1, 0 and 1, but they all output one decimal floats. The pandas.cut()
help does mention that the x-min and x-max values are extended with 0.1 % of the x-range, but I thought maybe include_lowest
could suppress this behaviour somehow. My current workaround involves importing numpy:
import numpy as np
bin_counts, edges = np.histogram(df.value, bins=7)
edges = [int(x) for x in edges]
df['binned_df_np'] = pd.cut(df.value, bins=edges, include_lowest=True)
sns.pointplot(x='binned_df_np', y='value', data=df)
plt.xticks(rotation=30, ha='right')
是否有一种方法可以直接使用 pandas.cut()
获得非负整数作为区间边界,而无需使用numpy?
Is there a way to obtain non-negative integers as the interval boundaries directly with pandas.cut()
without using numpy?
我刚刚注意到,指定 right = False
会使最低间隔移到0而不是-0.4.似乎优先于 include_lowest
,因为与 right = False
结合使用时,更改后者不会产生任何可见效果.以下间隔仍指定为小数点.
I just noticed that specifying right=False
makes the lowest interval shift to 0 rather than -0.4. It seems to take precedence over include_lowest
, as changing the latter does not have any visible effect in combination with right=False
. The following intervals are still specified with one decimal point.
推荐答案
您应专门设置 labels
参数
lower, higher = df['value'].min(), df['value'].max()
n_bins = 7
建立标签:
edges = range(lower, higher, (higher - lower)/n_bins) # the number of edges is 8
lbs = ['(%d, %d]'%(edges[i], edges[i+1]) for i in range(len(edges)-1)]
设置标签:
df['binned_df_pd'] = pd.cut(df.value, bins=n_bins, labels=lbs, include_lowest=True)
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