从getchar()读取输入会产生意外结果 [英] Reading input from getchar() giving unexpected results

问题描述

我有一个从终端读取PIN并将PIN和PIN长度存储在传递的变量中的功能.在第一次调用该函数时，我输入了预期的PIN和PIN长度.但是，在第二次调用此函数期间，第一个字符被省略.

I have a function which reads PIN from terminal and stores PIN and PIN length in the variables passed. On the first call to the function I get expected PIN and PIN length entered. However, during the second call to this function the first character is omitted.

/*
 * Function : read_pin(char *pin,int *pin_len)
 * Description : Read entered PIN and stores PIN in pin and pin length in pin_len
 */
int read_pin(unsigned char *pin,unsigned int *pin_len)
{
    int err = EXIT_SUCCESS;
    char ch;

    fflush(stdout);

    /* Pause to get pin (if removed, input is not read from terminal)*/
    getchar();     // i think,this is causing PROBLEM

    while( ((ch = getchar()) != '\n') )
    {
        pin[*pin_len] = ch;
        (*pin_len)++;
    }

    /* If newline at the end of the pin. You'll have to check that */
    if( pin[*pin_len-1] == '\n' )
    {
        pin[*pin_len-1] = '\0';
    }

    exit:
        return err;
}

此函数的调用:

printf("\nSelect session : ");
scanf("%d", &option);

printf("\nEnter old PIN: ");
read_pin(old_pin, &old_pin_len); // input: "1234" got: "1234"

fflush(stdout);

printf("\nEnter new PIN: ");
read_pin(new_pin, &new_pin_len); //input: "12345" got: "2345" (1 is omitted)

有人可以向我解释为什么我会出现这种行为以及如何解决该问题吗?

Can someone explain me why I am getting this kind of behaviour and how to fix it?

推荐答案

将第一个 getchar()移出 read_pin()

int read_pin(unsigned char *pin,unsigned int *pin_len)   
{
  int err = EXIT_SUCCESS;
  int ch;  /* getchar() returns int! */

  fflush(stdout);

  /* Pause to get pin (if removed, input is not read from terminal)*/

  while( ((ch = getchar()) != '\n') )

，并将其放在第一次调用 read_pin()的 scanf 调用之后.

and place it right after the scanf call before it calls read_pin() the 1st time.

  printf("\nSelect session : ");
  scanf("%d", &option);
  getchar();

这篇关于从getchar()读取输入会产生意外结果的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！