SwiftUI消除多个模态表 [英] SwiftUI Dismiss Multiple Modal Sheets

查看:52
本文介绍了SwiftUI消除多个模态表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在根视图中使用 .sheet(isPresented:self.$ showModal)来呈现模态.在模式中,我正在使用 NavigationView 引导用户浏览各个页面(用于用户个人资料构建器).

I am using .sheet(isPresented: self.$showModal) in my root view to present a modal. Within the modal, I am using NavigationView to take the user through various pages (for a user profile builder).

在导航堆栈的最后一页中,我正在使用 @Environment(\.presentationMode)varpresentationMode 和一个调用 self.presentationMode.wrappedValue.dismiss()的按钮代码>以消除模态.但是,这只会关闭导航堆栈中的最后一页,而我只是最后一页.我要做的是关闭整个导航堆栈,然后回到根视图.

In the last page of my navigation stack, I am using @Environment(\.presentationMode) var presentationMode and a button which calls self.presentationMode.wrappedValue.dismiss() to dismiss the modal. However, this only dismisses the last page in the navigation stack, and I just end up at the previous page. What I want to do is dismiss the entire navigation stack and end up back at the root view.

向下滑动以消除模态会产生所需的结果,但是我想通过按钮以编程方式执行此操作.

Swiping down to dismiss the modal produces the desired result, but I want to do this programatically with the button.

在SwiftUI中当前是否可行,还是在模式表中使用 NavigationView 时出现问题?

Is this currently possible in SwiftUI, or is this a problem with using NavigationView within a modal sheet?

推荐答案

您可以将showModal作为绑定传递到以下屏幕中,而不必使用presentationValue将showModal设置为false.

You can pass showModal as a binding into the following screens and instead of using presentationValue set showModal to false.

这篇关于SwiftUI消除多个模态表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆