将叉（）在iOS应用中可能是由苹果公司的审查程序被拒绝？ [英] Will fork() in iOS app likely be rejected by Apple's vetting process?

问题描述

我正在写一个机制（在iOS应用）来检测设备是否通过检查通过执行叉（应用程序沙箱的完整性越狱）; 。有谁知道，如果在尝试此调用会侵犯App Store的指引？

I'm writing a mechanism (in an iOS app) to detect whether a device is jailbroken by checking for App sandbox's integrity by doing a fork();. Does anyone know if attempting this call would violate App Store guidelines?

推荐答案

fork（）的（等）不会让你拒绝;由该香草操作系统拒绝操作不能同时提交被再现。
我有一个使用fork（）和（）调用来检查越狱的环境和他们没有得到拒绝了这个在AppStore上的应用：）

fork() (and other) will not get you rejected; operations that are denied by the vanilla os cannot be reproduced while in submission. I have applications on the appstore that use fork() and system() calls to check for jailbreak environment and none of them got rejected for this :)

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