如何将长整数转换为固定长度的16位二进制字符串? [英] How to convert a long to a fixed-length 16-bit binary string?

问题描述

我想将长整数转换为二进制，但是问题是我希望转换后得到固定的16位二进制结果，例如如果我将2转换为16位二进制，它应该给我0000000000000010，因为有人可以帮助我吗?

Hi i want to convert a long integer to binary but the problem is i want a fixed 16 bit binary result after conversion like if i convert 2 to 16 bit binary it should give me 0000000000000010 as ans can anyone help me ?

推荐答案

您最想要的是

Most likely what you want is Integer.toBinaryString(), combined with something to ensure that you get exactly 16 places:

int val = 2;
String bin = Integer.toBinaryString(0x10000 | val).substring(1);

这里的想法是通过在值的第17位放置1来获得零填充，然后使用 String.substring()截断由此创建的前导1，因此始终给您精确的16位二进制数字.(当然，只有在您确定输入是16位数字时，此方法才起作用.)

The idea here is to get the zero padding by putting a 1 in the 17th place of your value, and then use String.substring() to chop off the leading 1 this creates, thus always giving you exactly 16 binary digits. (This works, of course, only when you are certain that the input is a 16-bit number.)

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