Java正则表达式-拆分但忽略引号内的文本? [英] java Regex - split but ignore text inside quotes?

问题描述

仅使用正则表达式方法，即String.replaceAll和ArrayList方法如何将字符串拆分为标记，但忽略引号内存在的定界符?分隔符是不是字母数字或带引号的文本的任何字符

using only regular expression methods, the method String.replaceAll and ArrayList how can i split a String into tokens, but ignore delimiters that exist inside quotes? the delimiter is any character that is not alphanumeric or quoted text

例如:字符串:

你好^世界'这*有两个令牌'

hello^world'this*has two tokens'

应输出:

• 你好
• worldthis *有两个令牌

推荐答案

使用

Use a Matcher to identify the parts you want to keep, rather than the parts you want to split on:

String s = "hello^world'this*has two tokens'";
Pattern pattern = Pattern.compile("([a-zA-Z0-9]+|'[^']*')+");
Matcher matcher = pattern.matcher(s);
while (matcher.find()) {
    System.out.println(matcher.group(0));
}

查看其在线运行情况: ideone

See it working online: ideone

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