下载具有原始文件名的文件 [英] Download file with original file name

问题描述

在我的项目中，我正在上传文件.上传时，我将其原始文件名和扩展名保存在数据库中，并使用服务器上的某些 GUID 保存该文件，生成的GUID以及文件名和扩展名也存储在数据库中.

In my project I am uploading a file. While uploading, I am saving its original file name and extension in a database and saving that file with some GUID on server, generated GUID is also stored in database along with file name and extension.

例如-

-要上传的文件名是questions.docx

-File name for uploading is questions.docx

-然后orignalFileName将是问题"

-Then orignalFileName will be "questions"

-FileExtension将为".docx"

-FileExtension will be ".docx"

-以文件名"0c1b96d3-af54-40d1-814d-b863b7528b1c"上传文件

-File be get uploaded with file name as "0c1b96d3-af54-40d1-814d-b863b7528b1c"

上传工作正常..但是当我下载某些文件时，它以GUID文件名下载，在上述情况下，其名称为"0c1b96d3-af54-40d1-814d-b863b7528b1c".
如何下载文件其原始文件名为"questions.docx".

Uploading is working fine..but when I am downloading some file it gets downloaded with file name as the GUID in above case its "0c1b96d3-af54-40d1-814d-b863b7528b1c".
How can I download a file with its original file name i.e "questions.docx".

已添加代码

    /**
     * code to display files on browser
     */
    File file = null;
    FileInputStream fis = null;
    ByteArrayOutputStream bos = null;

    try {
        /**
         * C://DocumentLibrary// path of evidence library
         */
        String fileName = URLEncoder.encode(fileRepo.getRname(), "UTF-8");
        fileName = URLDecoder.decode(fileName, "ISO8859_1");
        response.setContentType("application/x-msdownload");            
        response.setHeader("Content-disposition", "attachment; filename="+ fileName);
        String newfilepath = "C://DocumentLibrary//" + systemFileName;
        file = new File(newfilepath);
        fis = new FileInputStream(file);
        bos = new ByteArrayOutputStream();
        int readNum;
        byte[] buf = new byte[1024];
        try {

            for (; (readNum = fis.read(buf)) != -1;) {
                bos.write(buf, 0, readNum);
            }
        } catch (IOException ex) {

        }
        ServletOutputStream out = response.getOutputStream();
        bos.writeTo(out);
    } catch (Exception e) {
        // TODO: handle exception
    } finally {
        if (file != null) {
            file = null;
        }
        if (fis != null) {
            fis.close();
        }
        if (bos.size() <= 0) {
            bos.flush();
            bos.close();
        }
    }

此代码是否完美?

推荐答案

您应将原始文件名设置为响应标头，如下所示:

You should set your origin file name into the response header, like below:

String fileName = URLEncoder.encode(tchCeResource.getRname(), "UTF-8");
fileName = URLDecoder.decode(fileName, "ISO8859_1");
response.setContentType("application/x-msdownload");            
response.setHeader("Content-disposition", "attachment; filename="+ fileName);

希望能为您提供帮助:)

Hope to help you:)

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