如何初始化静态ArrayList< myclass>在一排 [英] how to initialize static ArrayList<myclass> in one line

问题描述

我将MyClass作为

  MyClass(String，String，int); 

我知道如何以这种方式添加到ArrayList:

 <代码> MyClass.name = 名称";MyClass.address = 住址"; ADRESSMyClass.age =年龄； 

然后添加到ArrayList中所示:

  list.add(MyClass); 

但是现在我有很多静态形式的对象MyClass，我想添加

  ArrayList< MyClass>list = new ArrayList< MyClass>({"Name"，"Address"，age}; .....); 

我可以这样吗?还是谢谢

解决方案

您可以使用双括号初始化:-

<预> <代码>列表与LT; MyClass的>list = new ArrayList< MyClass>(){{add(new MyClass("name"，"address"，23));add(new MyClass("name2"，"address2"，45));}};

如您所见，内括号就像一个 initializer 块，用于一次初始化 list .

还要注意在大括号

末尾的分号

i have MyClass as

MyClass(String, String, int);

i know about how to add to add to ArrayList in this way:

MyClass.name = "Name";
MyClass.address = "adress";adress
MyClass.age = age;

then add to arrayList like:

list.add(MyClass);

but now i have many object MyClass in static form, i want to add

ArrayList<MyClass> list = new ArrayList<MyClass>({"Name","Address", age};.....);

can i do like this. thank anyway

解决方案

You can use double braces initialization: -

List<MyClass> list = new ArrayList<MyClass>() {
    {
        add(new MyClass("name", "address", 23));
        add(new MyClass("name2", "address2", 45));
    }
};

As you can see that, inner braces is just like an initializer block, which is used to initialize the list in one go..

Also note the semi-colon at the end of your double-braces

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