Java:String.contains匹配完全匹配的单词 [英] Java: String.contains matches exact word
本文介绍了Java:String.contains匹配完全匹配的单词的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在Java中
String term = "search engines"
String subterm_1 = "engine"
String subterm_2 = "engines"
如果我执行 term.contains(subterm_1)
,它将返回 true
.我不要我希望 subterm
与 term
If I do term.contains(subterm_1)
it returns true
. I don't want that. I want the subterm
to exactly match one of the words in term
因此,类似 term.contains(subterm_1)
的操作返回 false
和 term.contains(subterm_2)
的操作返回 true
Therefore something like term.contains(subterm_1)
returns false
and term.contains(subterm_2)
returns true
推荐答案
\ b匹配单词字符为[a-zA-Z0-9_]的单词边界.
\b Matches a word boundary where a word character is [a-zA-Z0-9_].
这应该对您有用,并且您可以轻松地重用此方法.
This should work for you, and you could easily reuse this method.
public class testMatcher {
public static void main(String[] args){
String source1="search engines";
String source2="search engine";
String subterm_1 = "engines";
String subterm_2 = "engine";
System.out.println(isContain(source1,subterm_1));
System.out.println(isContain(source2,subterm_1));
System.out.println(isContain(source1,subterm_2));
System.out.println(isContain(source2,subterm_2));
}
private static boolean isContain(String source, String subItem){
String pattern = "\\b"+subItem+"\\b";
Pattern p=Pattern.compile(pattern);
Matcher m=p.matcher(source);
return m.find();
}
}
输出:
true
false
false
true
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