Java equals()排序 [英] Java equals() ordering

问题描述

如果我尝试对Java中的空字符串执行 .equals()，则会引发空指针异常.我想知道，如果我想比较一个字符串是否等于某个常量字符串，我可以执行以下操作:

If I try to do a .equals() on a null string in java, a null pointer exception will be thrown. I am wondering, if I am trying to compare if a string is equal to some constant string, can I do the following:

MY_CONSTANT_STRING.equals(aStringVariable)

我知道它会起作用，但这真的是不好的代码吗?

I know it will work, but is this just really poor code?

推荐答案

这是一个标准的Java习惯用法，被戏称为

This is a standard Java idiom jokingly called a Yoda condition.

我个人更喜欢显式处理null情况，但是Yoda方法已被广泛使用，任何有经验的Java程序员都应该能够立即了解发生了什么.很好用.

Personally I prefer to handle the null case explicitly, but the Yoda way is used a lot and any experienced Java programmer should be able to understand what is going on immediately. It's fine to use.

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