正则表达式如何匹配所有标点符号，但排除某些条件 [英] Regex how to match all punctuations but exclude some conditions
问题描述
我可以使用 \ p {Punct} 来匹配所有标点符号(包括下划线).
I can use \p{Punct} to match all punctuations(including underscore).
我想完全排除一个单词内的所有撇号.为此，我正在使用(?< = [a-zA-Z])'(?= [a-zA-Z])
And I wanted to exclude all apostrophes strictly inside a word. For this I'm using (?<=[a-zA-Z])'(?=[a-zA-Z])
但是我不能让它们一起工作以匹配所有标点符号，但严格把单词内的撇号除外.
However I couldn't have them work together to match all punctuations except apostrophes strictly inside a word.
我应该使用什么?
示例:
我哥哥的应该不匹配.
我兄弟的应该匹配.
我的兄弟" 这些应该匹配.
推荐答案
您可以在此处组合三个条件.
You can combine three conditions here.
-
使用
[\ p {Punct}&& [^']]
匹配所有撇号而不是字母.
Match all apostrophe not followed by a letter.
匹配所有不带字母的撇号.
Match all apostrophe not preceded by a letter.
正则表达式: [\ p {Punct}&& [^']] |(?? lt !! [a-zA-Z])'|'(?![a-zA-Z])
说明:
-
[\\ p {Punct}&& [^']]从标点符号类中排除撇号.
[\\p{Punct}&&[^']]excludes apostrophe from punctuation class.
(?<！[a-zA-Z])'匹配不带字母的撇号.
(?<![a-zA-Z])' matches apostrophe not preceded by a letter.
'(?！[a-zA-Z])匹配撇号而不是字母.
'(?![a-zA-Z]) matches the apostrophe not followed by a letter.
RegexPlanet Fiddle
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