使用Java读取XML单行 [英] Read single XML line with Java

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问题描述

我正在尝试读取一个看起来像这样的XML行:

I'm trying to read a single XML line that looks like this:

<position lat="59.3252414125" long="18.0750236375" accuracy="1000"></position>

这里的目标是将"lat","long"和"accuracy"的值放入三个Java变量中.

The goal here is take the values of "lat", "long" and "accuracy" and put them in three Java variables.

我想我应该提到该行是从XML读取的,因此它看起来并不容易编辑.

I guess I should've mentioned that the line is read from an XML, so it's not easily editable as it would appear.

推荐答案

尝试:

    String s = "<position lat=\"59.3252414125\" long=\"18.0750236375\" accuracy=\"1000\"></position>";
    InputSource is = new InputSource(new StringReader(s));
    DOMParser dp = new DOMParser();
    dp.parse(is);
    Document doc = dp.getDocument();
    NodeList nl = doc.getElementsByTagName("position");
    Node n = nl.item(0);
    NamedNodeMap nnm = n.getAttributes();
    String lat = nnm.getNamedItem("lat").getFirstChild().getTextContent();
    String longg = nnm.getNamedItem("long").getFirstChild().getTextContent();
    String accuracy = nnm.getNamedItem("accuracy").getFirstChild().getTextContent();

建议的读物:

  • http://www.cafeconleche.org/books/xmljava/chapters/ch05.html
  • http://download.oracle.com/javase/tutorial/jaxp/index.html
  • Look into XOM it's too simple and good.

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