使用Java的完整链接提取 [英] Full Link Extraction using java
问题描述
我的目标是在从链接读取href属性时始终获取相同的字符串(在我的情况下为URI).例子:假设认为一个html文件具有许多链接,例如 a href ="index.html">
,但基本域为 http://www.domainname.com/index.html a href ="../index.html">
,但基本域为 http://www.domainname.com/dit/index.html
我如何正确获取所有链接意味着包括域名在内的完整链接?
我该如何在Java中做到这一点?
输入的是HTML,也就是说,需要从一堆HTML代码中提取正确的链接
My goal is to always get the same string (which is the URI in my case) while reading the href property from a link. Example:
Suppose think that a html file it have somany links like
a href="index.html">
but base domain is http://www.domainname.com/index.html
a href="../index.html">
but base domain is http://www.domainname.com/dit/index.html
how can i get all the link correctly means the full link including domain name?
how can i do that in java?
the input is HTML,that is,from a bunch of HTML code it need to extract correct link
推荐答案
您可以使用诸如 Jsoup .有一个 Node#absUrl()
正是您想要的.
You can do this using a fullworthy HTML parser like Jsoup. There's a Node#absUrl()
which does exactly what you want.
package com.stackoverflow.q3394298;
import java.net.URL;
import org.jsoup.Jsoup;
import org.jsoup.nodes.Document;
import org.jsoup.nodes.Element;
public class Test {
public static void main(String... args) throws Exception {
URL url = new URL("https://stackoverflow.com/questions/3394298/");
Document document = Jsoup.connect(url).get();
Element link = document.select("a.question-hyperlink").first();
System.out.println(link.attr("href"));
System.out.println(link.absUrl("href"));
}
}
为当前问题的标题链接打印(正确)以下内容:
which prints (correctly) the following for the title link of your current question:
/questions/3394298/full-link-extraction-using-java
https://stackoverflow.com/questions/3394298/full-link-extraction-using-java
出于您的目的,Jsoup可能还有其他(未发现的)优势.
Jsoup may have more other (undiscovered) advantages for your purpose as well.
更新:如果要在文档中选择所有链接,请执行以下操作:
Update: if you want to select all links in the document, then do as follows:
Elements links = document.select("a");
for (Element link : links) {
System.out.println(link.attr("href"));
System.out.println(link.absUrl("href"));
}
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