字符串函数如何计算字符串行中的分隔符 [英] String Functions how to count delimiter in string line

问题描述

我的字符串行如下:

A:B:C:D:E:F:G:H:I:J:K:L:M

A:B:C:D:E:F:G:H:I:J:K:L:M

这意味着定界符(:)计数为12.这行是有效的.

It means delimiter ( : ) count is 12 . This line is valid.

现在假设您有以下一行:

Now suppose you have a following line :

A:B:C:D:E:F:G:H :::::

A:B:C:D:E:F:G:H:::::

这行也是有效的，因为它包含12个定界符.其中存在8个值，其中4个值为空白.

This line is also valid because it contains 12 delimiter . where 8 values are present and 4 values are blank.

现在以下行应无效:

A:B:C:D:E:F:-无效-因为它仅包含6个值，但预期为12个.

A:B:C:D:E:F: -- Invalid - because it contains only 6 values but expected are 12.

该怎么做..?我尝试了以下代码，但未获得所需的输出:

how to do this .. ? I tried the following code , but not getting the desired output :

String strLine = "A:B:C:D:E:F:G:H:::::" ;
int delimiterCount = 12 ; 

String[] ValuesArray = strLine.split(":");
 if(ValuesArray.length != delimiterCounter){
 System.out.println(Invalid);
 }else {
 System.out.println("ValidLine");
 }

我将输出视为无效，因为它应该是有效的.

I am getting the output as Invalid where as it sould be Valid.

推荐答案

如果您想使用 split ，并且它的确不是一个坏方法(尽管可能适用于这种特殊情况)，需要将-1作为第二个参数传递给 split ，否则它将删除空字符串.

If you want to use split, and it's not a bad approach really (although it might be for this particular situation), you need to pass -1 as the second argument to split otherwise it removes empty strings.

请参见 http://ideone.com/gaUw5 .

很高兴知道有关 split 的知识.有些语言要求-1，有些则不需要.

It is good to know this about split. Some languages require the -1 and some do not.

代码

class Main {
    public static void main(String[] args) {
        String line = "A:B:C:D:E:F:G:H:::::" ;
        int delimiterCount = 12 ; 

        String[] values = line.split(":", -1);
        if (values.length != delimiterCount + 1) {
            System.out.println("Invalid Line");
        } else {
            System.out.println("Valid Line");
        }
    }
}

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