精确匹配8位数字的Java RegEx [英] Java RegEx that matches exactly 8 digits
本文介绍了精确匹配8位数字的Java RegEx的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个简单的RegEx,它应该查找8位数字:
I have a simple RegEx that was supposed to look for 8 digits number:
String number = scanner.findInLine("\\d{8}");
但是事实证明,它还匹配9个或更多的数字.如何修复此RegEx以精确匹配8位数字?
But it turns out, it also matches 9 and more digits number. How to fix this RegEx to match exactly 8 digits?
例如:12345678应该匹配,而1234567和123456789不应该.
For example: 12345678 should be matched, while 1234567, and 123456789 should not.
推荐答案
尝试一下:
\ b
被称为单词边界,它将对您的正则表达式说数字在8以后结束
\b
is known as word boundary it will say to your regex that numbers end after 8
String number = scanner.findInLine("\\b\\d{8}\\b");
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