我如何使用下划线获取基于对象属性的唯一数组 [英] How can I get a unique array based on object property using underscore

问题描述

我有一个对象数组，我想从中获得一个仅基于单个属性唯一的新数组，有没有简单的方法来实现这一点?

I have an array of objects and I want to get a new array from it that is unique based only on a single property, is there a simple way to achieve this?

例如.

[ { id: 1, name: 'bob' }, { id: 1, name: 'bill' }, { id: 1, name: 'bill' } ]

将删除2个名称= bill的对象.

Would result in 2 objects with name = bill removed once.

推荐答案

使用 uniq 函数

var destArray = _.uniq(sourceArray, function(x){
    return x.name;
});

或单行版本

var destArray = _.uniq(sourceArray, x => x.name);

从文档中

使用===测试对象相等性，产生数组的无重复版本.如果您事先知道数组已排序，则为isSorted传递true将运行更快的算法.如果要基于转换计算唯一项，请传递迭代器函数.

Produces a duplicate-free version of the array, using === to test object equality. If you know in advance that the array is sorted, passing true for isSorted will run a much faster algorithm. If you want to compute unique items based on a transformation, pass an iterator function.

在上面的示例中，该函数使用对象名称来确定唯一性.

In the above example, the function uses the objects name in order to determine uniqueness.

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