为什么Math.min([1,2])返回NaN? [英] Why does Math.min([1,2]) return NaN?

问题描述

我已经调试了大约一个小时的代码，看起来 Math.min([1,2])返回 NaN .

I've been debugging this code for about an hour, and it looks like Math.min([1,2]) returns NaN.

var int_array = [1,2]
console.log(Math.min(int_array)) //prints NaN, but expect 1
isNaN(Math.min(int_array))===true

推荐答案

The Math.min() function actually expects a series of numbers, but it doesn't know how to handle an actual array, so it is blowing up.

您可以使用 spread运算符 ... :

var int_array = [1,2];
console.log(Math.min(...int_array)); // returns 1

您还可以通过 Function.apply() 函数本质上会做同样的事情，但并不那么漂亮:

You could also accomplish this via the Function.apply() function that would essentially do the same thing but isn't as pretty :

var int_array = [1,2];
console.log(Math.min.apply(null,int_array)); // returns 1

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