有条件地与react-router链接 [英] Conditionally linking with react-router Link
本文介绍了有条件地与react-router链接的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的React组件中有一种情况:如果 this.props.isComingFromModal
为false,我希望将某些元素包装在 Link
组件中.
I have a situation in my React component which is: i want some elements to be wrappend in a Link
component if this.props.isComingFromModal
is false.
我做了什么(JSX):
What i did (JSX):
<If condition={!this.props.isComingFromModal}>
<Link
to={{ pathname: `vendors/${benefit.vendor.id}`, state: { modal: false } }}
>
<img
className="Benefit__vendor__thumb"
src={benefit.vendor.tinyLogoUrl}
alt="Ponto Frio"
/>
<div className="Benefit__vendor__info">
<h2 className="Benefit__vendor__title">{benefit.vendor.tradingName}</h2>
<div className="rating">
<Rating
readonly
initialRate={benefit.vendor.rating}
className="rating"
fractions={2}
empty="icon-rating icon-rating--empty fa fa-star fa-2x"
full="icon-rating fa fa-star fa-2x"
/>
</div>
</div>
</Link>
<Else />
<img
className="Benefit__vendor__thumb"
src={benefit.vendor.tinyLogoUrl}
alt="Ponto Frio"
/>
<div className="Benefit__vendor__info">
<h2 className="Benefit__vendor__title">{benefit.vendor.tradingName}</h2>
<div className="rating">
<Rating
readonly
initialRate={benefit.vendor.rating}
className="rating"
fractions={2}
empty="icon-rating icon-rating--empty fa fa-star fa-2x"
full="icon-rating fa fa-star fa-2x"
/>
</div>
</div>
</If>
但是我这是重复的.我不能只做(JSX)这样的事情吗?
But I this this is kind of repetitive. Can't I just do something like (JSX)
<Link
to={{ pathname: `vendors/${benefit.vendor.id}`, state: { modal: false } }}
condition={!this.props.isComingFromModal}
>
<img
className="Benefit__vendor__thumb"
src={benefit.vendor.tinyLogoUrl}
alt="Ponto Frio"
/>
<div className="Benefit__vendor__info">
<h2 className="Benefit__vendor__title">{benefit.vendor.tradingName}</h2>
<div className="rating">
<Rating
readonly
initialRate={benefit.vendor.rating}
className="rating"
fractions={2}
empty="icon-rating icon-rating--empty fa fa-star fa-2x"
full="icon-rating fa fa-star fa-2x"
/>
</div>
</div>
</Link>
在这种假设的情况下,即使 this.props.isComingFromModal
,我也会展示Link组件.有办法做到这一点吗?
In this hypothetical scenario, i would exhibit the Link component just if this.props.isComingFromModal
. There is a way to do something this?
推荐答案
我的简单功能解决方案:
My simple functional solution:
const ConditionalLink = ({ children, to, condition }) => (!!condition && to)
? <Link to={to}>{children}</Link>
: <>{children}</>;
然后您可以像这样使用它:
Then you can use it like this:
<ConditionalLink to="/path" condition={!isComingFromModal}
conditional link
</ConditionalLink>
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