使用underscore.js过滤数组 [英] Filtering array with underscore.js

问题描述

我试图过滤一些对象以更好地理解JS，并且使用了underscore.js

I am trying to filter some objects in my attempt to understand JS better and I'm using underscore.js

我来自C#背景，习惯于LINQ，但是下划线并不完全相同.

I come from a C# background and am used to LINQ however underscore is not quite the same.

您能帮我根据定义的测试筛选出此数组吗，我遇到的问题是数组上的array属性. Where 运算符与C#不同，这是我通常用来过滤项目的C#.

Can you help me filter out this array based on the defined test, the issue I'm having is the array property on the array. The Where operator is diffeernt to C# which is what I'd normally use to filter items.

products = [
       { name: "Sonoma", ingredients: ["artichoke", "sundried tomatoes", "mushrooms"], containsNuts: false },
       { name: "Pizza Primavera", ingredients: ["roma", "sundried tomatoes", "goats cheese", "rosemary"], containsNuts: false },
       { name: "South Of The Border", ingredients: ["black beans", "jalapenos", "mushrooms"], containsNuts: false },
       { name: "Blue Moon", ingredients: ["blue cheese", "garlic", "walnuts"], containsNuts: true },
       { name: "Taste Of Athens", ingredients: ["spinach", "kalamata olives", "sesame seeds"], containsNuts: true }
    ];

it("given I'm allergic to nuts and hate mushrooms, it should find a pizza I can eat (functional)", function () {

      var productsICanEat = [];

      //This works but was hoping I could do the mushroom check as well in the same line
      var noNuts = _(products).filter(function (x) { return !x.containsNuts;});

      var noMushrooms = _(noNuts).reject(function(x){ return !_(x.ingredients).any(function(y){return y === "mushrooms";});});


      console.log(noMushrooms);

      var count = productsICanEat.length;
      expect(productsICanEat.length).toBe(count);
  });

推荐答案

您只需要从 reject 回调中删除！，使其看起来像这样:

You just need to remove the ! from the reject callback so that it look like this:

var noMushrooms = _(noNuts).reject(function(x){ 
    return _(x.ingredients).any(function(y){return y === "mushrooms";});
});

否则，您将拒绝不包含蘑菇的蘑菇而不是包含蘑菇的蘑菇.

Otherwise you're rejecting the ones that don't contain mushrooms instead of those that do.

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