JavaScript RegEx:将具有动态长度的字符串格式化为块格式 [英] JavaScript RegEx: Format string with dynamic length to block format
问题描述
以下RegEx格式将字符串赋予以下输出块模式:
The following RegEx formats given string to following output block pattern:
123 456 78 90 (= 3位3位2位2位)
123 456 78 90 (= 3 digits 3 digits 2 digits 2 digits )
RegEx:
string.replace(/^(\d{3})(\d{3})(\d{2})(\d{2})$/g, '$1 $2 $3 $4');
仅当给定的输入字符串与10位数字的确切长度匹配时，此示例才有效.
This example only works, if given input string matches exact length of 10 digits.
如何调整正则表达式以适应每个字符串长度?
How can I adjust the RegEx to work with every string length?
- 1234->123 4
- 1234567->123 456 7
- 123456789->123 456 78 9
- 1234567890123->123 456 78 90 12 3
背景:当用户输入数字时，我想直接设置表单输入字段的输入字符串的格式...
Background: I want to format the input string of a form input field directly, when a user enters the number...
推荐答案
在后面使用允许动态长度声明的现代Javascript后缀，您可以使用此正则表达式进行匹配:
Using modern Javascript lookbehind that allows dynamic length assertion, you can use this regex to match:
/(?<=^(?:\d{6}(?:\d{2})*|(?:\d{3}){1,2}))(?=\d+$)/g
只需将其替换为一个空格，即""
Just replace that with a single space i.e. " "
隐藏:
-
(?< =:开始声明-
^(?:\ d {6}(?:\ d {2})*:确保我们后面有6位数字，后跟0或多个数字对 -
|:或 -
(?:\ d {3}){1,2}):让我们后面有一组或两组3位数字集
(?<=: Start assertion^(?:\d{6}(?:\d{2})*: Make sure we have 6 digits followed by 0 or more digits pair behind|: OR(?:\d{3}){1,2}): Make we have one or two sets of 3 digit sets behind
提前提醒:
-
(?= \ d + $):确保我们至少有一位数字
(?=\d+$): Make sure we have at least a digit ahead
这篇关于JavaScript RegEx:将具有动态长度的字符串格式化为块格式的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
-
