如何将对象或分组参数传递给SQL IN子句? [英] How to pass objects or grouped params to SQL IN clause?

问题描述

我需要使用JPA通过匹配表中的2个分组参数来查找记录，但是我的问题是，即使有可能，我也不知道如何在SQL中传递对象或分组参数.

I need using JPA to find records by matching 2 grouped parameters from a table but my problem is that I don't know how to pass an object or grouped parameter in SQL, if that is possible at all.

假设我们有User表:

Let's say we have the User table:

USER_TABLE

name VARCHAR,
email VARCHAR,
address VARCHAR

我需要找到分组名称和电子邮件匹配的所有用户.像这样:

I need to find all users where grouped name and email match. Something like this:

SELECT FROM USER_TABLE 
WHERE (name, email) 
IN (('John', 'john@mail'), ('Oliver', 'oliver@mail'));

它在SQL工具中有效，但是现在我需要从Java使用此SQL

It works in SQL tool but now I need to use this SQL from Java

为此，我将其覆盖以接受参数

To do so I udpated it to accept a parameter

SELECT FROM USER_TABLE 
WHERE (name, email) 
IN (?);

所以我的问题是如何传递参数或将其分组?

So my question is HOW do I pass parameters or so that they will be grouped?

我试图创建一个如下所示的参数，但由于它不是有效类型而无法使用

I tried to create a parameter as it is below but it won't work because it is not a valid type

String param = "('John', 'john@mail'), ('Oliver', 'oliver@mail')";
db.execute(sql, param)

那有可能吗?

推荐答案

您可以这样做:

SELECT FROM USER_TABLE 
WHERE (name, email) 
IN ((?, ?), (?, ?));

每个参数代替一个单个标量值，而不是值列表，并且不替代任何其他SQL语法(例如括号).您需要将所有括号放入准备好的语句中，然后仅对值使用参数.

Each parameter takes the place of a single scalar value, not a list of values, and not any other SQL syntax like parentheses. You need to put all the parens into your prepared statement, then use parameters only for the values.

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