删除Laravel上的对象 [英] Delete object on laravel

问题描述

我正在学习laravel，现在我试图删除没有形式的对象.我想使用js来检测用户何时单击删除"按钮并将通知返回给控制器.然后，具有ID为ID的删除对象的控制器已从JS文件返回.

I'm learning laravel, and now i trying to delete object without form. i want to use js to detect when user click delete's button and return notify to controller. Then controller with delete object with id has returned from JS file.

这是刀片文件

@extends ('layouts.master')

@section ('head.title')
Blog
@stop

@section ('body.content')
    <div class="container">
        <div class="row">
            <div class="col-sm-6 col-sm-offset-3">
            </div>
        </div>

        <form class="form-show">
            <div class="row">
                <div class="col-sm-6 col-sm-offset-3">
                    <h2> {{ $article->title}} </h2>
                    <p>  {{ $article->content}} </p>
                </div>

                <div class="row">
                    <div class="col-sm-6 col-sm-offset-3">
                        <a href=" {{ route('article.edit', $article->id) }}" class="btn btn-info">Update</a>
                        <button id="delete-button" type="submit" class="btn btn-primary">Delete</button>

                    </div>
                </div>
            </div>
        </form>
    </div>
       <script src="{{ asset('/js/jshow.js') }}"></script>
@stop

这是控制器文件

类ArticlesController扩展了Controller{受保护的$ articleModel;

class ArticlesController extends Controller { protected $articleModel;

    public function __construct(Article $article){
        $this->articleModel = $article;
    }

    public function index(){
        $articles = $this->articleModel->getListArticles();
        // $articles = Article::paginate(10);
        return view('articles.index',compact('articles'));
    }    

    public function show($id){
        // $article = Article::find($id);
        $article = $this->articleModel->getArticleWithID($id);
        return view('articles.show',compact('article'));
    }

    public function delete($id){
        $this->articleModel->deleteArticle($id);
        return redirect()->route('articles.index');
    }
}

这是JS文件

var deleteButton = document.getElementById("delete-button");
var idPost = document.getElementById("")
deleteButton.onclick = function() { 
    alert('Click to delete');
    return false; 
}

推荐答案

您需要使用 jQuery JS库中的> $.ajax .

You need to use $.ajax from the jQuery JS library.

尝试理解并做点事情，如果遇到困难，请回来.

Try to understand and to do something, then come back if you any have difficulties.

像 Jerodev 所说，AJAX调用可以在没有jQuery的情况下完成，但是我发现jQuery方法更容易理解.在此处上阅读有关使用纯JavaScript的AJAX的更多信息.

Like Jerodev said, AJAX calls can be done without jQuery, but I find the jQuery method more understandable. Check here to read more about AJAX using plain JavaScript.

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