如果在FormRequest Laravel中验证失败，如何添加额外的数据作为响应 [英] How to add extra data in response if Validation fails in FormRequest Laravel

问题描述

如果在FormRequest中验证失败，我需要添加自定义标签作为响应.

I need to add custom tag in response if the validation fails in FormRequest.

<?php

namespace App\Http\Requests;

use Illuminate\Foundation\Http\FormRequest;

class StoreMessage extends FormRequest
{
    /**
     * Determine if the user is authorized to make this request.
     *
     * @return bool
     */
    public function authorize()
    {
        return true;
    }

    /**
     * Get the validation rules that apply to the request.
     *
     * @return array
     */
    public function rules()
    {
        return [
            'name' => 'required|max:100',
            'email' => 'required|email',
            'message' => 'required|max:1000'
        ];
    }

    public function withValidator(\Illuminate\Validation\Validator $validator)
    {
        $validator->after(function ($validator) {

               if($validator->fails()) {
                   $validator->errors()->add('status', 'error');
               }

        });
    }

}

如果我的任何验证都仅失败，那么我需要在json响应中添加 status = error ，否则我需要添加 status = success .

If my any of the validation fails only then I need to add status = error in json response else I need to add status = success.

我的响应状态也嵌套在 errors 标签下，我需要将其设置为0级.

Also my response status is nested under errors tag I need it to be at level 0.

    {
  "message": "The given data was invalid.",
  "errors": {
    "name": [
      "The name may not be greater than 100 characters."
    ],
    "status": [
      "error"
    ]
  }
}

目的是我正在发送Ajax请求以提交表单，我需要一个标志来标识是否发生错误.有没有更好的方法可以做到这一点.如果我问一个愚蠢的问题，请原谅我.我是laravel的新手.任何帮助将不胜感激.

Purpose of this is I am sending Ajax request to submit a form i need a flag to identify whether error occurred or not. Is there any better way to do this. Pardon me if I am asking silly question. I am newbie to laravel. Any help would be appreciated.

推荐答案

从文档中(搜索"AJAX"):

From the docs (search for "AJAX"):

在AJAX请求期间使用validate方法时，Laravel将不会生成重定向响应.相反，Laravel会生成一个包含所有验证错误的JSON响应.此JSON响应将以422 HTTP状态代码发送.

When using the validate method during an AJAX request, Laravel will not generate a redirect response. Instead, Laravel generates a JSON response containing all of the validation errors. This JSON response will be sent with a 422 HTTP status code.

在您的Javascript中，您可以在 a .fail()处理程序.

In your Javascript, you can catch this happening in a .fail() handler.

更新简单示例，不处理格式化多个验证错误，但可以为您提供想法:

UPDATE Simple example, doesn't handle formatting multiple validation errors but gives you the idea:

$.ajax( ... )
.fail(function(xhr, status, error) {
    if (error === 'Unprocessable Entity') {
        // validation failure
        var msg = '';    
        for (error in xhr.responseJSON) {
            msg += xhr.responseJSON[error];
        };
        alert(msg);
    }
});

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