如何离开当前应用程序并启动另一个应用程序的活动? [英] How to leave the current app and launch an activity of another app?

问题描述

我有一个简单的Android应用程序，需要在特定条件下启动另一个应用程序，并且在应用程序启动时需要检查条件.也就是说，要么继续启动我的应用程序，要么只是启动另一个应用程序:

I have a simple Android app that needs to launch another app under certain condition, and I will need to check the condition upon the app launch. That is, either continue to launch my app or just launch another app:

if (A == true) {
 launch another activity of another app
 leave the current app without creating the main activity
} else {
 launch the main activity of the current app
}

有人可以让我知道如何处理A ==真实情况吗?我能够启动另一个应用程序的活动，但是即使不打开主活动也无法离开当前应用程序.

Could anyone please let me know how to deal with A == true case? I am able to launch another app's activity but I have trouble leaving the current app without even opening the main activity.

任何帮助将不胜感激！

推荐答案

您可以使用以下意图启动其他应用程序

You can launch other application using following intent

Intent LaunchIntent = getPackageManager().getLaunchIntentForPackage("com.example.abc");//pass the packagename of app you want to open
startActivity( LaunchIntent );

如果您不知道要启动的应用程序的软件包名称，请尝试

If you don't know the package name of application that you wanted to launch then try your hand on

PackageManager pm;
pm = getPackageManager();
//  get a list of installed apps.
packages = pm.getInstalledApplications(0);

传递您要打开的应用程序的程序包名称如果A == true，则可以使用此

Pass the packagename of app you want to open You can use this if A == true

否则，您可以启动MainActivity为

else You can launch the MainActivity as

startActivity(new Intent(CurrentActivity.this,MainActivity.class));

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