sed:多行的有条件合并 [英] sed: conditional merge of multiple lines

问题描述

我需要基于模式使用sed合并文件的行.例如:

I need to merge line of a file using sed based on a pattern. eg:

输入文件:

X1 A B C D E F

\+ G H I J 1 

\+ LK T PP E OO 2

X2 DDF F Y 

\+ J W Q 

....

预期输出:

X1 A B C D E F G H I J 1 LK T PP E OO 2

X2 DDF F Y J W Q 

..

---

我想在vi编辑器(:％s/\ n +//g)中可以等同于wat

---

I would like to equivalent of wat is possible in vi editor (:%s/\n+/ /g)

在网上搜索时，我找到了一个解决方案，从逻辑上讲应该是可行的

Searching the web I found a solution, which logically should have worked

sed -e'{:a;N;s/\ n +//g;ta}'infile

sed -e '{:a; N; s/\n+/ /g; ta}' infile

但是此命令违背了我的理解和逻辑，并产生了输出

But this command defies my understanding and logic, and has produced output

X1 A B C D E F

\+ G H I J 1 LK T PP E OO 2
X2 DDF F Y 

\+ J W Q 

....

欢迎任何想法，并且提前致谢

Any ideas are welcome, & Thanks in advance

Srisurya

推荐答案

这可能对您有用:

sed ':a;$!N;s/\n+//;ta;P;D' file

说明:

• :a 是循环占位符
• $！N 表示是否将文件末尾附加到当前行.
• s/\ n +//表示删除行尾的加号
• ta 表示最后一次替换是否有效，分支到 a 循环占位符
• P 打印到第一行.
• D 删除直到并包括第一条换行符.

• :a is a loop placeholder
• $!N means if not end-of-file append next line to current line.
• s/\n+// means delete an end on line followed by a plus sign
• ta means if last substitution worked branch to a loop placeholder
• P print upto the first newline.
• D delete upto and including the first newline.

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