从C中的另一个文件链接静态函数 [英] Linking static function from another file in c

问题描述

我有两个源文件:A.c和B.c

I have two source files: A.c and B.c

A.c有一个函数call_me:

A.c has a function, call_me:

static int call_me();

void call_me_register()
{
    register_call_me(call_me);
}

如您所见，call_me函数用作变量，因此在A.o中具有call_me的符号

As you can see, call_me function is used as variable so it has a symbol of call_me in A.o

现在，我想在B.c文件中调用此call_me函数.

Now, I want to call this call_me function in B.c file.

static int call_me();

void call_call_me()
{
    call_me();
}

如果我尝试链接B.o，则出现链接错误，即没有对call_me的引用.

If I try to link B.o, I've got an link error, that no such reference of call_me.

在这里，约束如下:由于某种原因，我无法修改A.c.在B.c的A.c中有没有叫"call_me"的电话?

Here, the constraint is the following: I can not modify A.c for some reason. Is there a any to call 'call_me' in A.c in B.c?

推荐答案

C中静态函数的可见性仅限于声明了它们的文件.因此，如果u在Ac中声明一个并从另一个文件中调用该函数，则bc您将收到一个链接错误，提示该函数未引用.希望此问题可以解决..

Visibility of Static functions in C is restricted to only the file in which they are declared.so if u declare one in A.c and call that function from another file b.c you will get a link error that the function is unreferenced..Hope this will solve your problem..

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