如何使用C在Linux中检测系统是否将进入待机状态 [英] How to detect whether system is going to standby in Linux using C

问题描述

我想知道如何在Linux中使用C来检测系统是否将进入待机模式.为此，我在Windows中找到了一条名为 WM_POWERBROADCAST 的消息，该消息会在发送之前发送进入睡眠模式.

I want to know how I can detect whether the system is going to a standby mode in Linux using C. I found a message called WM_POWERBROADCAST in windows for that purpose, which sends this message before going to the sleep mode.

对于Linux，C语言中还有其他替代方法吗?

Is there any alternatives in C, for Linux?

我听说DBus可以用于相同的目的，有人可以进一步解释吗?

I heard that DBus can be used for same purpose, could somebody explain it more?

推荐答案

最后我找到了解决方案.

Finally I found a solution.

我们可以使用pm实用程序.

We can use the pm utility for that.

如果将任何shell脚本放在/etc/pm/sleep.d文件夹中，它将在系统进入睡眠状态之前和系统恢复之后自动执行.

If you put any shell script in /etc/pm/sleep.d folder it will be executed automatically just before the system going to sleep and after the system is resumed.

内容将类似于

#!/bin/bash
case $1 in
suspend)
    #suspending to RAM
    /home/harikrishnan/Desktop/sleepd Sleeping
    ;;
resume)
    #resume from suspend
    sleep 3
    /home/harikrishnan/Desktop/sleepd Woken
    ;;
esac

此处将使用参数执行/home/harikrishnan/Desktop/sleeped程序

here it will execute the /home/harikrishnan/Desktop/sleepd program with the arguments

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