在python中将进程运行到/dev/null [英] run a process to /dev/null in python

问题描述

如何在Python中运行以下代码?

How do I run the following in Python?

/some/path/and/exec arg > /dev/null

我知道了:

call(["/some/path/and/exec","arg"])

如何将 exec 进程的输出插入到/dev/null 并保持python进程的打印输出正常?在这种情况下，不要将所有内容都重定向到stdout吗?

How do I insert the output of the exec process to /dev/null and keep the print output of my python process as usual? As in, don't redirect everything to stdout?

推荐答案

对于Python 3.3和更高版本，只需使用

For Python 3.3 and later, just use subprocess.DEVNULL:

call(["/some/path/and/exec","arg"], stdout=DEVNULL, stderr=DEVNULL)

请注意，这将同时重定向 stdout 和 stderr .如果您只想重定向 stdout (如您的 sh 行所暗示的那样)，则省去 stderr = DEVNULL 部分.

Note that this redirects both stdout and stderr. If you only wanted to redirect stdout (as your sh line implies you might), leave out the stderr=DEVNULL part.

如果您需要与旧版本兼容，则可以使用 os.devnull .因此，这适用于2.6(含3.3)以上的所有版本:

If you need to be compatible with older versions, you can use os.devnull. So, this works for everything from 2.6 on (including 3.3):

with open(os.devnull, 'w') as devnull:
    call(["/some/path/and/exec","arg"], stdout=devnull, stderr=devnull)

或者，对于2.4及更高版本(仍包括3.3):

Or, for 2.4 and later (still including 3.3):

devnull = open(os.devnull, 'w')
try:
    call(["/some/path/and/exec","arg"], stdout=devnull, stderr=devnull)
finally:
    devnull.close()

在2.4之前，没有 subprocess 模块，因此可以回想起.

Before 2.4, there was no subprocess module, so that's as far back as you can reasonably go.

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