删除外壳中以字符开头的行 [英] Remove the lines starting with a character in shell

问题描述

我的数据集为:

file.txt
de
fds
fds
a
sa
1
2
3
1
}

我想删除所有以字符或特殊字符开头的行.所以我的档案是:

I would like to delete all the lines starting with characters or special characters. So my outfile is:

out.txt
1
2
3
1

我可以使用'sed'手动完成此操作，但是我正在为此寻找合适的命令.

I could do it manually with 'sed', but I am looking for a suitable command for this.

我的代码:

sed -i '/d//g' file.txt
sed -i '/f//g' file.txt
sed -i '/a//g' file.txt
sed -i '/s//g' file.txt
sed -i '/}//g' file.txt

推荐答案

使用 grep 和 -E 选项进行正则表达式(或简称egrep):

Use grep with -E option for regex (or egrep in short):

grep -E "^[0-9].*" file.txt

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