netcat的换行问题 [英] new line issue with netcat

问题描述

我正在使用以下命令将一些字符串发送到udp监听服务器.

I am using below command to send some strings to udp listening server.

回显"A 192.168.192.168" |nc -u 192.168.2.1 1234

echo "A 192.168.192.168" | nc -u 192.168.2.1 1234

但是服务器在回显的字符串中尾随'\ n'.

but the server is getting trailing '\n' in echoed string.

我也尝试过下面的命令，但是失败了

I have tried below command too, but failed

回显"A 192.168.192.168" |nc -uC 192.168.2.1 1234

echo "A 192.168.192.168" | nc -uC 192.168.2.1 1234

如何删除尾随的换行符?我在nc中有什么特殊选择吗?

How can I remove that trailing new line character ?? Do I have any special option in nc ??

推荐答案

echo 通常提供 -n 标志.这不是标准的.

echo usually provides -n flag. This is not standard.

string 要写入标准输出的字符串.如果第一个操作数是-n，或者任何一个操作数包含反斜杠('\')char-演员，结果是实现定义的.

string A string to be written to standard output. If the first operand is -n, or if any of the operands contain a backslash ( '\' ) char‐ acter, the results are implementation-defined.

在符合XSI的系统上，如果第一个操作数为-n，则应将其视为字符串，而不是选项.

On XSI-conformant systems, if the first operand is -n, it shall be treated as a string, not an option.

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我建议使用 printf

printf "A 192.168.192.168" | nc -u 192.168.2.1 1234

除非被告知，否则

printf 不会添加新行，这是标准行为.

printf doesnt append a new line unless it is told to, and it's standard behavior.

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