如何从存储在char *指针中的name调用c函数? [英] How to call a c function from name , which is stored in a char* pointer?

问题描述

我想按名称动态调用一个函数，例如，假设具有以下函数和字符串:

I wanted to dynamically call a function by its name , e.g , suppose have the following function and string:

void do_fork()
{
   printf ("Fork called.\n");

}

char *pFunc = "do_fork";

现在我只需要通过 * pFunc 来调用 do_fork().那有可能吗?

Now i need to call do_fork() just by *pFunc. So is that possible ?

欢迎使用C/C ++代码，非常感谢！

Either C/C++ code is welcomed , many thanks !

推荐答案

C和C ++都没有足够的反射来实现此功能，因此您将必须实现自己的方案.

Neither C nor C++ have enough reflection to do this out of the box, so you will have to implement your own scheme.

在C ++中，或多或少的规范方法是使用字符串映射到函数指针.像这样:

In C++, the more or less canonical way to do that is using a map of strings to function pointers. Something like this:

typedef void (*func_t)();
typedef std::map<std::string,func_t> func_map_t;

// fill the map
func_map_t func_map;
func_map["do_fork"] = &do_fork;
func_map["frgl"] = &frgl;

// search a function in the map
func_map_t::const_iterator it = func_map.find("do_fork");
if( it == func_map.end() ) throw "You need error handling here!"
(*it->second)();

当然，这仅限于具有完全相同签名的功能.但是，通过使用 std :: function 和 std :: bind 而不是普通的函数指针，可以稍微解除此限制(以包含合理兼容的签名).

Of course, this is limited to functions with exactly the same signature. However, this limitation can be somewhat lifted (to encompass reasonably compatible signatures) by using std::function and std::bind instead of a plain function pointer.

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