为什么此subprocess.check_call()不起作用? [英] Why doesn't this subprocess.check_call() work?

问题描述

我正在Ubuntu 12上使用Python 2.7运行这些代码片段.

I'm running these snippets with Python 2.7 on Ubuntu 12.

import subprocess
args = ['rsync', '--rsh="ssh"', '/tmp/a/', '127.0.0.1:/tmp/b/']
subprocess.check_call(args)

失败

import subprocess
args = ['rsync', '--rsh="ssh"', '/tmp/a/', '127.0.0.1:/tmp/b/']
call_string = ' '.join(args)
subprocess.check_call(call_string)

作品

第一个代码段导致rsync收到无效的命令行.使用此选项的简短版本( -e )没有任何区别.如果我删除-rsh 部分，它将正常工作.

The first code snippet results in rsync getting an invalid command line. Using the short version of this option (-e) doesn't make any difference. If I remove the --rsh part it works fine.

使用 shell = True 没有任何区别.消除"ssh"中的引号没有什么区别，我希望保留引号，以便可以将参数传递给ssh.

Using shell=True doesn't make any difference. Eliminating the quotes from "ssh" doesn't make any difference and I'd like to keep the quotes so I can pass arguments to ssh.

出什么问题了?

推荐答案

删除 ssh 周围的引号；外壳程序通常会解析它们并传递参数而没有引用:

Remove the quotes around ssh; the shell would normally have parsed those and passed on the argument without the quoting:

import subprocess
args = ['rsync', '--rsh=ssh', '/tmp/a/', '127.0.0.1:/tmp/b/']
subprocess.check_call(args)

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