计算2个列表之间的重复项 [英] Count duplicates between 2 lists

问题描述

a = [1, 2, 9, 5, 1]
b = [9, 8, 7, 6, 5]

我想计算两个列表之间重复的次数.因此，使用上述方法，我想返回2的计数，因为两个列表共有9和5.

I want to count the number of duplicates between the two lists. So using the above, I want to return a count of 2 because 9 and 5 are common to both lists.

我尝试了类似的方法，但是效果不佳.

I tried something like this but it didn't quite work.

def filter_(x, y):
    count = 0
    for num in y:
        if num in x:
            count += 1
            return count

推荐答案

更好的方法:

>>> a = [1, 2, 9, 5, 1]
>>> b = [9, 8, 7, 6, 5]
>>> len(set(a) & set(b))     # & is intersection - elements common to both
2 

为什么您的代码不起作用:

Why your code doesn't work:

>>> def filter_(x, y):
...     count = 0
...     for num in y:
...             if num in x:
...                     count += 1
...     return count
... 
>>> filter_(a, b)
2

您的返回计数在for循环内，并且返回时未完成执行.

Your return count was inside the for loop and it returned without execution being complete.

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