从清单中退回具有最小值的项目 [英] Return Item from List with Minimum Value

问题描述

我有一个物品清单:

List<Item> items = new List<Item>();
items.add(new Item("cow", 4));
items.add(new Item("pig", 7));
items.add(new Item("dog", 12));

我想用最小的 Value (其中的数字是那个 Value )检索该项目.我该怎么办?

I want to retreive the item with the minimum Value (where the numbers are that Value). How would I do that?

我正在尝试避免讨厌的 foreach 循环.我正在寻找符合以下条件的东西:

I am trying to avoid a nasty foreach loop. I am looking for something along the lines of:

return items.Min(Value);

推荐答案

您可以先获取最小值，然后获取具有最小值的项目:

You can get the minimum value first, then get the item that has the minimum value:

var minValue = items.Min(x => x.Value);
var item = items.First(x => x.Value == minValue);

您也可以在效率不高的一行中执行此操作，因为它将对每个项目执行 Min :

You can also do that in one line that won't be efficient because it will perform Min for each item:

var item = items.First(x => x.Value == items.Min(x => x.Value));

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