Python将字符串转换为数组赋值 [英] Python convert string to array assignment

问题描述

在我的应用程序中，我收到一个字符串'abc [0] = 123'

In my application I am receiving a string 'abc[0]=123'

我想将此字符串转换为项目数组.我已经尝试过 eval()对我不起作用.我知道数组名称 abc ，但是每次的项数都会不同.

I want to convert this string to an array of items. I have tried eval() it didnt work for me. I know the array name abc but the number of items will be different in each time.

我可以分割字符串，获取数组索引并执行.但是我想知道是否有任何直接方法可以将此字符串转换为数组插入.我非常感谢任何建议.

I can split the string, get array index and do. But I would like to know if there is any direct way to convert this string as an array insert. I would greately appreciate any suggestion.

推荐答案

这是一个根据php规则解析网址的函数(即使用方括号创建数组或嵌套结构):

Here's a function for parsing urls according to php rules (i.e. using square brackets to create arrays or nested structures):

import urlparse, re

def parse_qs_as_php(qs):

    def sint(x):
        try:
            return int(x)
        except ValueError:
            return x

    def nested(rest, base, val):
        curr, rest = base, re.findall(r'\[(.*?)\]', rest)
        while rest:
            curr = curr.setdefault(
                sint(rest.pop(0) or len(curr)), 
                {} if rest else val)
        return base

    def dtol(d):
        if not hasattr(d, 'items'):
            return d
        if sorted(d) == range(len(d)):
            return [d[x] for x in range(len(d))]
        return {k:dtol(v) for k, v in d.items()}

    r = {}
    for key, val in urlparse.parse_qsl(qs):
        id, rest = re.match(r'^(\w+)(.*)$', key).groups()
        r[id] = nested(rest, r.get(id, {}), val) if rest else val
    return dtol(r)

示例:

qs = 'one=1&abc[0]=123&abc[1]=345&foo[bar][baz]=555'
print parse_qs_as_php(qs)
# {'abc': ['123', '345'], 'foo': {'bar': {'baz': '555'}}, 'one': '1'}

这篇关于Python将字符串转换为数组赋值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！