在python中的列表中找到子列表的位置 [英] Find the position of sublist in a list in python

问题描述

例如，我在Python中有两个列表x和y.假设 x = [0,1,2,3,4,5,6,7] 和 y = [3,4,5] ，显然y是x的子列表，而子列表y在x中的位置是 3 .换句话说，我试图获得一个判断一个列表是否为另一个列表中的子列表的函数.如果是这样，我也想弄清楚子列表的位置.

For example, I have two list x and y in Python. Supposing x = [0,1,2,3,4,5,6,7] and y = [3,4,5], it is clear that y is a sublist of x and the position of sublist y in x is 3. In other words，I'm trying to get a function that judges whether a list is a sublist in another list. If so,I would like to figure out the position of the sublist as well.

我不知道我是否可以使用任何现成的功能.如果没有，那么有谁知道我如何使用某种有效的方法来实现它.

I don't know if there has any off-the-shelf function I can use. If not, does anyone have an idea of how I can achieve it using some effective method.

感谢您的任何帮助！

推荐答案

x = [0,1,2,3,4,5,6,7]
y = [3,4,5]

occ = [i for i, a in enumerate(x) if a == y[0]]

for b in occ:
      if x[b:b+len(y)] == y:
           print 'YES-- SUBLIST at : ', b
           break
      if len(occ)-1 ==  occ.index(b):
           print 'NO SUBLIST'
           break

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