&"getEnumerator不是函数&"Javascript(在线SharePoint) [英] "getEnumerator is not a function" Javascript (Sharepoint Online)

问题描述

有人知道我为什么得到

未捕获的TypeError:list.getEnumerator不是函数"

"Uncaught TypeError: list.getEnumerator is not a function"

在我的OnSuccess()函数中?

in my OnSuccess() function?

当我尝试获取网站集中所有列表的标题时，此代码运行良好.

This code worked fine before, when I tried to get the Titles of all lists in my site collection.

现在，我想在分配给 testIssues 的列表中获得分配给John Doe的所有行的标题.

Now I want to get the titles of all rows assigned to John Doe, in my list called testIssues.

我错过了什么?

'use strict';
var clientContext = new SP.ClientContext.get_current();
var hostweburl = decodeURIComponent(getQueryStringParameter("SPHostUrl"));
var parentContext = new SP.AppContextSite(clientContext, hostweburl);
var parentWeb = parentContext.get_web();
var list = parentWeb.get_lists().getByTitle("testIssues");
var listItems;

$(document).ready(function () {

});

function VisaLista() {
    var camlQuery = new SP.CamlQuery();
    camlQuery.set_viewXml("<View><Query><Where><Geq><FieldRef Name='p32c'/>" +
    "<Value Type='User'>John doe</Value></Geq></Where></Query></View>");
    listItems = list.getItems(camlQuery);
    clientContext.load(listItems);
    clientContext.executeQueryAsync(OnSuccess, OnFail);
}

function OnSuccess() {
    var listString;
    var listEnumerator = list.getEnumerator();
    while (listEnumerator.moveNext()) {
        var currentItem = listEnumerator.get_current();
        listString += "<br/> " + currentItem.get_title();
    }
    $('#divAllaListor').html(listString);
}

function OnFail(sender, args) {
    alert('Failed, Error:' + args.get_message());
}

function getQueryStringParameter(param) {
    var params = document.URL.split("?")[1].split("&");
    var strParams = "";
    for (var i = 0; i < params.length; i = i + 1) {
        var singleParam = params[i].split("=");
        if (singleParam[0] == param) {
            return singleParam[1];
        }
    }
}

推荐答案

您正在将列表项加载到名为 listItems 而不是 list 的变量中.

You're loading the list items into a variable named listItems, not list.

尝试 var listEnumerator = listItems.getEnumerator();

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