Python-在缺少索引的位置用零填充元组列表 [英] Python - filling a list of tuples with zeros in places of missing indexes

问题描述

我有一个元组列表:

[(0.0, 287999.70000000007),
(1.0, 161123.23000000001),
(2.0, 93724.140000000014),
(3.0, 60347.309999999983),
(4.0, 55687.239999999998),
(5.0, 29501.349999999999),
(6.0, 14993.920000000002),
(7.0, 14941.970000000001),
(8.0, 13066.229999999998),
(9.0, 10101.040000000001),
(10.0, 4151.6900000000005),
(11.0, 2998.8899999999999),
(12.0, 1548.9300000000001),
(15.0, 1595.54),
(16.0, 1435.98),
(17.0, 1383.01)]

可以看出，缺少索引(13和14).我想用零填充缺失的索引:

As can be seen, there are missing indexes (13 and 14). I want to fill the missing indexes with zeros:

[(0.0, 287999.70000000007),
(1.0, 161123.23000000001),
(2.0, 93724.140000000014),
(3.0, 60347.309999999983),
(4.0, 55687.239999999998),
(5.0, 29501.349999999999),
(6.0, 14993.920000000002),
(7.0, 14941.970000000001),
(8.0, 13066.229999999998),
(9.0, 10101.040000000001),
(10.0, 4151.6900000000005),
(11.0, 2998.8899999999999),
(12.0, 1548.9300000000001),
(13.0, 0),
(14.0, 0),
(15.0, 1595.54),
(16.0, 1435.98),
(17.0, 1383.01)]

我在 for循环上做了一些丑陋的事情(我没有添加它，因为我认为它不会对任何事情有所贡献...)，但是我想知道是否有任何优雅的方法可以解决这个问题?(也许使用 list comprehension 的3-4行).

I did something ugly with for loop (I didn't add it cause I don't think it will contribute to anything...), but I was wondering is there any elegant way to resolve this problem? (maybe 3-4 lines with list comprehension).

推荐答案

简单的 for 循环可能比列表理解更容易:

Just a straight for loop is probably easier than a list comprehension:

data = [(0.0, 287999.70000000007),
(1.0, 161123.23000000001),
(2.0, 93724.140000000014),
(3.0, 60347.309999999983),
(4.0, 55687.239999999998),
(5.0, 29501.349999999999),
(6.0, 14993.920000000002),
(7.0, 14941.970000000001),
(8.0, 13066.229999999998),
(9.0, 10101.040000000001),
(10.0, 4151.6900000000005),
(11.0, 2998.8899999999999),
(12.0, 1548.9300000000001),
(15.0, 1595.54),
(16.0, 1435.98),
(17.0, 1383.01)]

result = []
last = 0.0
for d in data:
    while last < d[0]:
        result.append((last, 0))
        last += 1
    result.append(d)
    last = d[0]+1

稍短(包括列表理解):

Slightly shorter (and including a list comprehension):

result, last = [], 0.0
for d in data:
    result.extend((r,0) for r in range(int(last), int(d[0])))
    result.append(d)
    last = d[0]+1

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